(2/3)x^2+20=2

Solution for (2/3)x^2+20=2 equation:

(2/3)x^2+20=2

We move all terms to the left:

(2/3)x^2+20-(2)=0


Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x^2+20-2=0

We add all the numbers together, and all the variables

(+2/3)x^2+18=0

We multiply all the terms by the denominator


(+2+18*3)x^2=0

We add all the numbers together, and all the variables

56x^2=0

a = 56; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·56·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{112}=0$